COMEDK · Physics · 24. Electromagnetic Waves
If \(\mu_{0}\) is permeability of free space and \(\varepsilon_{0}\) is permittivity of free space, then the speed of light in vacuum is given by
- A \(\sqrt{\mu_{0} \varepsilon_{0}}\)
- B \(\sqrt{\mu_{0} / \varepsilon_{0}}\)
- C \(\sqrt{\frac{1}{\mu_{0} \varepsilon_{0}}}\)
- D \(\cdot \sqrt{\varepsilon_{0} / \mu_{0}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{\frac{1}{\mu_{0} \varepsilon_{0}}}\)
Step-by-step Solution
Detailed explanation
Speed of light in terms of permittivity of free space \(\varepsilon_{0}\) and permeability of free space \(\mu_{0}\) is given as \[ C=\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}=\sqrt{\frac{1}{\mu_{0} \varepsilon_{0}}} \]
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