(B) water at 4^{\circ} \mathrm{C}

(C) water, in which soap does not lather

(D) compound of heavy oxygen and heavy hydrogen

COMEDK · Physics · 29. Nuclear Physics

Heavy water is

A compound of deuterium and oxygen
B water at \(4^{\circ} \mathrm{C}\)
C water, in which soap does not lather
D compound of heavy oxygen and heavy hydrogen

Verified Solution

Answer & Solution

Correct Answer

(A) compound of deuterium and oxygen

Step-by-step Solution

Detailed explanation

Heavy water \(\left(\mathrm{D}_{2} \mathrm{O}\right)\) contains heavy hydrogen or deuterium and oxygen.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Match the Coordination compounds given in Column I with their characteristic features listed in Column II.

S.No.	Coordination compounds	S.No.	Characteristic features
W	\([Co(NH_3)_5Cl]Cl_2\)	P	Oxidation state \(= +3\), Configuration \(= d^5\), \(\mu = 5.92\) BM
X	\(K_4[Mn(CN)_6]\)	Q	Oxidation state \(= +3\), Configuration \(= d^3\), \(\mu = 3.87\) BM
Y	\([CrCl_2(py)_3]\)	R	Oxidation state \(= +3\), Configuration \(= d^6\), \(\mu = 0\) BM
Z	\(Cs[FeCl_4]\)	S	Oxidation state \(= +2\), Configuration \(= d^5\), \(\mu = 1.732\) BM

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