COMEDK · Physics · 17. Electrostatics
Four charges each with charge \(+q\) are placed at the four corners of a square of side \(l\), a charge \(\frac{-q}{4}\) is at centre of the square. Force on the charge at the centre due to other charges is
- A \(\frac{K q^2}{l^2}\)
- B \(K \frac{\sqrt{2} q^2}{l^2}\)
- C zero
- D \(K \frac{2 \sqrt{2} q^2}{l^2}\)
Answer & Solution
Correct Answer
(C) zero
Step-by-step Solution
Detailed explanation
Force due to each \(q\) charge on \(-q / 4\) is balanced by diagonally opposite charge. \(F_{\text {net }}=0\)
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