COMEDK · Physics · 15. Oscillations
Force constant of interatomic bond, in a certain element, is \(7.1\ Nm^{-1}\). If the atom oscillates in SHM in a certain direction, what is its frequency?
Given: Mole weight of the given element is 108g and Avagadro's number \(= 6.023 \times 10^{23}\ g\ mol^{-1}\)
- A \(6.667 \times 10^{12}\ s^{-1}\)
- B \(0.005 \times 10^{12}\ s^{-1}\)
- C \(3.45 \times 10^{22}\ s^{-1}\)
- D \(1 \times 10^{12}\ s^{-1}\)
Answer & Solution
Correct Answer
(D) \(1 \times 10^{12}\ s^{-1}\)
Step-by-step Solution
Detailed explanation
Mass of a single atom is given by \(m = \dfrac{M}{N_A}\) Substituting the given values: \(m = \dfrac{108 \times 10^{-3}}{6.023 \times 10^{23}} \approx 1.793 \times 10^{-25}\ kg\) The frequency of oscillation of the atom in simple harmonic motion is given by:…
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