COMEDK · Physics · 20. Magnetic Properties of Matter
For a short magnet, the magnetic field on the axial line at a distance 10 cm from its centre is \(1.6 \mathrm{~m} \times 10^{-7} \mathrm{~T}\). What is the magnetic field on its equatorial line at the same distance 10 cm from its centre?
- A \(1.6 \times 10^{-7} T\)
- B \(0.8 \times 10^{-7} T\)
- C \(4.8 \times 10^{-7} T\)
- D \(3.2 \times 10^{-8} T\)
Answer & Solution
Correct Answer
(B) \(0.8 \times 10^{-7} T\)
Step-by-step Solution
Detailed explanation
The magnetic field \(B_{axial}\) on the axial line of a short magnetic dipole at a distance \(d\) is given by the formula \(B_{axial} = \dfrac{\mu_0}{4\pi} \dfrac{2M}{d^3}\). The magnetic field \(B_{equatorial}\) on the equatorial line of the same short magnetic dipole at the…
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