COMEDK · Physics · 17. Electrostatics
Five charges, '\(q\)' each are placed at the comers of a regular pentagon of side '\(a\)' as shown in figure. First, charge from '\(A\)' is removed with other charges intact, then charge at '\(A\)' is replaced with an equal opposite charge. The ratio of magnitudes of electric fields at \(\mathrm{O}\), without charge at \(A\) and that with equal and opposite charge at \(A\) is

- A 1 : 4
- B 4 : 1
- C 2 : 1
- D 1 : 2
Answer & Solution
Correct Answer
(D) 1 : 2
Step-by-step Solution
Detailed explanation
Let the electric field due to a charge \(q\) at a corner of the regular pentagon at the center \(O\) be \(\vec{E}\). The distance from each corner to the center \(O\) is \(r\). By symmetry, the sum of the electric fields due to all five charges \(q\) at the corners…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- A block of a certain material is heated to a temperature of 500° C and then placed on a large ice block. If 1.455 kg of ice melts, find the mass of the block. Specific heat of the material is \(0.39\ Jg^{-1}C^{-1}\) and heat of fusion of water is \(335\ Jg^{-1}\).COMEDK 2026 Medium
- The equation of a progressive wave can be given by \(y=15 \sin (660 \pi t-0.02 \pi x) \mathrm{cm}\). The frequency of the wave isCOMEDK 2020 Easy
- If the length of a wire is increased by \(20 \%\) by stretching it, then its resistance is increased toCOMEDK 2024 Medium
- The threshold frequency for a metal surface is '\(n_0\)'. A photo electric current '\(I\)' is produced when it is exposed to a light of frequency \(\left(\dfrac{11}{6}\right) \mathrm{n}_{\mathrm{o}}\) and intensity \(\mathrm{I}_{\mathrm{n}}\). If both the frequency and intensity are halved, the new photoelectric current '\(\mathrm{I}^1\)' will become:COMEDK 2024 Medium
- An electron is accelerated through a potential difference of \(45.5 \mathrm{~V}\). The velocity acquired by it is \(\left(\right.\) in \(\mathrm{ms}^{-1}\) )COMEDK 2013 Easy
- When a body moves in a circular path, no work is done by the force sinceCOMEDK 2013 Easy
More PYQs from COMEDK
- The function \(f(x)=\left(\frac{\log _{e}(1+a x)-\log _{e}(1-b x)}{x}\right)\) is
undefined at \(x=0\). The value which should be assigned to \(f\) at \(x=0\) so that it is continuous at \(x=0\) isCOMEDK 2018 Medium - Two statements, one Assertion (A) and the other Reason (R) are given. Choose the correct option.
Assertion: Maltose, a disaccharide, is a reducing sugar and is obtained by the partial hydrolysis of starch in presence of the enzyme diastase.
Reason: Hydrolysis of one mole of Maltose gives one mole each of \(\alpha-\mathrm{D}-\) Glucose and \(\beta-\) D-Fructose.COMEDK 2025 Medium - A stone dropped from the top of the tower reaches ground in \(4 \mathrm{~s}\). Height of the tower is \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)COMEDK 2016 Easy
- If 2 moles of \(\mathrm{C}_6 \mathrm{H}_6(\mathrm{~g})\) are completely burnt \(4100 \mathrm{~kJ}\) of heat is liberated. If \(\Delta H^{\circ}\) for \(\mathrm{CO}_2(\mathrm{~g})\) and \(\mathrm{H}_2 \mathrm{O}(l)\) are \(-410\) and \(-285 \mathrm{~kJ}\) per mole respectively then the heat of formation of \(\mathrm{C}_2 \mathrm{H}_6(g)\) isCOMEDK 2023 Medium
- \(\mathrm{X} \rightarrow 2 \mathrm{Y}\) is a first order reaction where \(1.0 \mathrm{~mol} / \mathrm{L}\) of the reactant yields \(0.4 \mathrm{~mol} / \mathrm{L}\) of Y in 200 minutes. Calculate the half-life period of the reaction in minutes.COMEDK 2025 Medium
- Observe the given below reaction.
Aqueous \(\mathrm{CuSO}_4 \xrightarrow{\text { Excess } a q \mathrm{KCN}} A \xrightarrow{\mathrm{H}_2 \mathrm{~S}} B\)
A, B respectively areCOMEDK 2024 Medium