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COMEDK · Physics · 17. Electrostatics

Five charges, '\(q\)' each are placed at the comers of a regular pentagon of side '\(a\)' as shown in figure. First, charge from '\(A\)' is removed with other charges intact, then charge at '\(A\)' is replaced with an equal opposite charge. The ratio of magnitudes of electric fields at \(\mathrm{O}\), without charge at \(A\) and that with equal and opposite charge at \(A\) is

  1. A 1 : 4
  2. B 4 : 1
  3. C 2 : 1
  4. D 1 : 2
Verified Solution

Answer & Solution

Correct Answer

(D) 1 : 2

Step-by-step Solution

Detailed explanation

Let the electric field due to a charge \(q\) at a corner of the regular pentagon at the center \(O\) be \(\vec{E}\). The distance from each corner to the center \(O\) is \(r\). By symmetry, the sum of the electric fields due to all five charges \(q\) at the corners…
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