COMEDK · Physics · 25. Ray Optics
Figure below shows a lens of refractive index, \(\mu=1.4\). \(C_1\) and \(C_2\) are the centres of curvature of the two faces of the lens of radii of curvature \(4 \mathrm{~cm}\) and \(8 \mathrm{~cm}\) respectively.
The lens behaves as a
- A converging lens of focal length \(12 \mathrm{~cm}\)
- B diverging lens of focal length \(20 \mathrm{~cm}\)
- C converging lens of focal length \(20 \mathrm{~cm}\)
- D diverging lens of focal length \(12 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) converging lens of focal length \(20 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
The lens shown is a meniscus lens. We use the lens maker's formula: \(\dfrac{1}{f} = (\mu - 1) \left( \dfrac{1}{R_1} - \dfrac{1}{R_2} \right)\). For the given lens, the first surface (left) is convex towards the object space, so its center of curvature \(C_1\) is to the right.…
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