COMEDK · Physics · 5. Laws of Motion
\(\mathrm{F}_{\mathrm{A}}, \mathrm{F}_{\mathrm{B}}\) and \(\mathrm{F}_{\mathrm{C}}\) are three forces acting at point \(\mathrm{P}\) as shown in figure. The whole system is in equilibrium state. The magnitude of \(\mathrm{F}_{\mathrm{A}}\) is
- A 100 N
- B 83.3 N
- C 73.2 N
- D 89.6 N
Answer & Solution
Correct Answer
(C) 73.2 N
Step-by-step Solution
Detailed explanation
The system is in equilibrium at point P. We resolve the forces \(F_A\) and \(F_B\) into their horizontal and vertical components. For horizontal equilibrium: \(F_B \cos(45^{\circ}) - F_A \cos(30^{\circ}) = 0\) \(F_B \dfrac{1}{\sqrt{2}} = F_A \dfrac{\sqrt{3}}{2}\)…
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