COMEDK · Physics · 28. Atomic Physics
Excitation energy of a hydrogen like ion in its first excitation state is \(40.8 \mathrm{eV}\). Energy needed to remove the electron from the ion in ground state is
- A \(54.4 \mathrm{eV}\)
- B \(13.6 \mathrm{eV}\)
- C \(40.8 \mathrm{eV}\)
- D \(27.2 \mathrm{eV}\)
Answer & Solution
Correct Answer
(A) \(54.4 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
Excitation energy of hydrogen like ion in its first excitation state, \(\Delta E=40.8 \mathrm{eV}\) For the hydrogen like ion, energy in the ground state \((n=1)\), \[ E=\frac{-13.6 Z^{2}}{n^{2}} \mathrm{eV}=-13.6 Z^{2} \mathrm{eV} \] Energy in the first excited state,…
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