COMEDK · Physics · 12. Thermal Properties of Matter
Consider a compound slab consisting of two different materials having equal lengths, thickness and thermal conductivities \(K\) and \(2 K\) respectively. The equivalent thermal conductivity of the slab is
- A \(\sqrt{2} K\)
- B \(3 K\)
- C \(\dfrac{4}{3} K\)
- D \(\dfrac{2}{3} K\)
Answer & Solution
Correct Answer
(C) \(\dfrac{4}{3} K\)
Step-by-step Solution
Detailed explanation
Let the length of each slab be \(L\) and the cross-sectional area be \(A\). The thermal conductivities are \(K_1 = K\) and \(K_2 = 2K\). When the slabs are connected in series, the total thermal resistance \(R_{eq}\) is the sum of individual resistances \(R_1\) and \(R_2\).…
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