COMEDK · Physics · 13. Thermodynamics
Carnot cycle of an engine is given below

Total work done by the gas in one cycle is
- A \(\mu R T_{2} \log \dfrac{V_{2}}{V_{1}}-\mu R T_{1} \log \dfrac{V_{3}}{V_{4}}\)
- B \(\mu R T_{1} \log \dfrac{V_{2}}{V_{1}}-\mu R T_{2} \log \dfrac{V_{3}}{V_{4}}\)
- C \(\mu R T_{1} \log \dfrac{V_{2}}{V_{1}}+\mu R T_{2} \log \dfrac{V_{3}}{V_{4}}\)
- D Zero
Answer & Solution
Correct Answer
(B) \(\mu R T_{1} \log \dfrac{V_{2}}{V_{1}}-\mu R T_{2} \log \dfrac{V_{3}}{V_{4}}\)
Step-by-step Solution
Detailed explanation
The Carnot cycle has two isothermal and two adiabatic processes. \(P \to Q\): Isothermal expansion at \(T_1\) (\(T_1 = T_2\)): \(W_{PQ} = \mu RT_1 \ln\dfrac{V_2}{V_1}\) \(Q \to R\): Adiabatic expansion: \(W_{QR} = \dfrac{\mu R(T_2 - T_3)}{\gamma - 1}\) \(R \to S\): Isothermal…
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