COMEDK · Physics · 18. Capacitance
By connecting two given capacitors, a technician was able to make two new capacitors having the effective capacitance \(12.5 \mu \mathrm{F}\) and \(2 \mu \mathrm{F}\). What would be the capacitance of the given capacitors?
- A \(8.5 \mu \mathrm{~F}\) and \(4 \mu \mathrm{~F}\)
- B \(6.5 \mu \mathrm{~F}\) and \(6 \mu \mathrm{~F}\)
- C \(10 \mu \mathrm{~F}\) and \(2.5 \mu \mathrm{~F}\)
- D \(10.5 \mu \mathrm{~F}\) and \(2 \mu \mathrm{~F}\)
Answer & Solution
Correct Answer
(C) \(10 \mu \mathrm{~F}\) and \(2.5 \mu \mathrm{~F}\)
Step-by-step Solution
Detailed explanation
Let the capacitances of the two capacitors be \(C_1\) and \(C_2\). When connected in parallel, the effective capacitance is \(C_p = C_1 + C_2 = 12.5 \mu F\). When connected in series, the effective capacitance is \(C_s = \dfrac{C_1 C_2}{C_1 + C_2} = 2 \mu F\). Substituting…
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