COMEDK · Physics · 12. Thermal Properties of Matter
Assuming, \(R=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) and \(\gamma=1.4\) the values of \(C_{p}\) and \(C_{V}\) of a gas are
- A \(29.05 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 20.75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
- B \(20.75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 29.05 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
- C \(16.60 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 8.300 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
- D \(8.300 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 16.60 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
Answer & Solution
Correct Answer
(A) \(29.05 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 20.75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, \(\gamma=1.4=\frac{C_{p}}{C_{V}}\) \(\Rightarrow \quad C_{p}=1.4 C_{V}\) Also, \(\quad R=C_{p}-C_{V}=8.3 \quad \text{(given)}\) \(\Rightarrow \quad 1.4 C_{V}-C_{V}=8.3\) or \(\quad C_{V}=\frac{8.3}{0.4}=20.75 \mathrm{Jmol}^{-1} \mathrm{~K}^{-1}\)…
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