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COMEDK · Physics · 12. Thermal Properties of Matter

Assuming, \(R=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) and \(\gamma=1.4\) the values of \(C_{p}\) and \(C_{V}\) of a gas are

  1. A \(29.05 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 20.75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
  2. B \(20.75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 29.05 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
  3. C \(16.60 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 8.300 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
  4. D \(8.300 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 16.60 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(29.05 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, 20.75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)

Step-by-step Solution

Detailed explanation

Given, \(\gamma=1.4=\frac{C_{p}}{C_{V}}\) \(\Rightarrow \quad C_{p}=1.4 C_{V}\) Also, \(\quad R=C_{p}-C_{V}=8.3 \quad \text{(given)}\) \(\Rightarrow \quad 1.4 C_{V}-C_{V}=8.3\) or \(\quad C_{V}=\frac{8.3}{0.4}=20.75 \mathrm{Jmol}^{-1} \mathrm{~K}^{-1}\)…
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