COMEDK · Physics · 8. Rotational Motion
Applying a constant torque the speed of a flywheel is increased from 1800 rpm to 2400 rpm in 10 seconds. The number of revolutions made by the flywheel during this time is:
- A \(350\)
- B \(700\)
- C \(900\)
- D \(2100\)
Answer & Solution
Correct Answer
(A) \(350\)
Step-by-step Solution
Detailed explanation
Initial angular velocity \(\omega_0 = 1800 \text{ rpm} = \dfrac{1800 \times 2\pi}{60} \text{ rad/s} = 60\pi \text{ rad/s}\). Final angular velocity \(\omega = 2400 \text{ rpm} = \dfrac{2400 \times 2\pi}{60} \text{ rad/s} = 80\pi \text{ rad/s}\). Time interval…
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