COMEDK · Physics · 32. Experimental Physics
An unknown resistance \(R_{1}\) is connected in series with a resistance of \(10 \Omega\). This combination is connected to one gap of a meter bridge, while a resistance \(R_{2}\) is connected in the other gap. The balance point is at \(50 \mathrm{~cm}\). Now, when the \(10 \Omega\) resistance is removed the balance point shifts to \(40 \mathrm{~cm}\). The value of \(R_{1}\) (in ohm) is
- A 60
- B 40
- C 20
- D 10
Answer & Solution
Correct Answer
(C) 20
Step-by-step Solution
Detailed explanation
\(R_{1}\) is connected with \(10 \Omega\) resistance, According to question, a balanced point is obtained at 50 . Thus, \(\frac{R_{1}+10}{R_{2}}=\frac{50}{50}\) \[ \Rightarrow \quad R_{2}=R_{1}+10 \] When \(10 \Omega\) is removed the balanced point shifts to \(40 \mathrm{~cm}\).…
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