COMEDK · Physics · 25. Ray Optics
An object of height \(h\) is placed midway between \(f\) and \(2 f\) in front of a biconvex lens. A real inverted image is captured on a screen placed a little beyond \(2 f\) on the other side of the lens. If the whole arrangement is immersed in water without disturbing the object, lens and the screen positions, then the new image formed will be
- A Magnified real inverted image on the same side of the lens where the object is placed
- B Diminished real inverted image on the other side of the lens between \(f\) and \(2 f\)
- C Magnified real inverted image on the other side of the lens beyond \(2 f\)
- D Magnified virtual erect image on the same side of the lens where the object is placed
Answer & Solution
Correct Answer
(D) Magnified virtual erect image on the same side of the lens where the object is placed
Step-by-step Solution
Detailed explanation
The focal length of a lens in a medium of refractive index \(n_m\) is given by the lens maker formula: \(\dfrac{1}{f_m} = (\dfrac{n_l}{n_m} - 1)(\dfrac{1}{R_1} - \dfrac{1}{R_2})\). Initially, in air (\(n_m = 1\)), the focal length is \(f\). When immersed in water (…
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