COMEDK · Physics · 3. Motion In One Dimension
An object is dropped from a certain point A at a height 'h' from the ground. During it's journey straight downwards, the object passes points B and C such that the ratio of time taken \(t_1\) to cover AB and \(t_2\) to cover BC is 1: \((\sqrt{2} - 1)\). What is the ratio of distances AB:BC ?
- A \(1:\sqrt{2}\)
- B \(\sqrt{2}:1\)
- C \(1:1\)
- D \((\sqrt{2} - 1):1\)
Answer & Solution
Correct Answer
(C) \(1:1\)
Step-by-step Solution
Detailed explanation
Let the time taken to travel from A to B be \(t_1 = t\). The time taken to travel from B to C is \(t_2 = (\sqrt{2} - 1)t\). The total time taken to travel from A to C is \(t_{AC} = t_1 + t_2 = t + (\sqrt{2} - 1)t = \sqrt{2}t\). Since the object is dropped from rest at A, the…
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