COMEDK · Physics · 30. Semiconductors
An LED is constructed from a \(p-n\) junction diode using GaAsP. The energy gap is \(1.9 \mathrm{eV}\). The wavelength of the light emitted will be equal to
- A \(10.4 \times 10^{-26} \mathrm{~m}\)
- B \(654 \mathrm{~nm}\)
- C \(654 Å\)
- D \(654 \times 10^{-11} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(654 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
The energy of light of wavelength \(\lambda\) is given by \(E=h v=\frac{h c}{\lambda}\) Here, \(h=\) Planck's constant \(=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}\)…
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