COMEDK · Physics · 12. Thermal Properties of Matter
An iron piece of mass \(200 \mathrm{~g}\) is kept inside a furnace for some time and then put in a calorimeter of water equivalent \(20 \mathrm{~g}\) containing \(230 \mathrm{~g}\) of water at \(20 \mathrm{C}\). The steady state temperature attained by the mixture is \(60^{\circ}\). The temperature of the furnace is (Specific heat capacity of iron is \(470 \mathrm{~J~kg}^{-1} \mathrm{C}^{-1}\) )
- A 953.6\(^\circ\)C
- B 893.6\(^\circ\)C
- C 506.8\(^\circ\)C
- D 464.7\(^\circ\)C
Answer & Solution
Correct Answer
(C) 506.8\(^\circ\)C
Step-by-step Solution
Detailed explanation
Let \(T\) be the temperature of the furnace. The heat lost by the iron piece is equal to the heat gained by the calorimeter and the water. Mass of iron \(m_{Fe} = 0.2 \text{ kg}\). Specific heat of iron \(c_{Fe} = 470 \text{ J kg}^{-1} \text{ C}^{-1}\). Water equivalent of…
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