COMEDK · Physics · 13. Thermodynamics
An ideal gas goes from state \(A\) to state \(B\) via three different processes as indicated in the \(p\)-\(V\) diagram. If \(Q_1, Q_2\) and \(Q_3\) indicate the heat absorbed by the three processes and \(\Delta U_1, \Delta U_2\) and \(\Delta U_3\) indicate the change in internal energy along the three processes respectively, then
- A \(Q_1 > Q_2 > Q_3\) and \(\Delta U_1=\Delta U_2=\Delta U_3\)
- B \(Q_1=Q_2=Q_3\) and \(\Delta U_1 > \Delta U_2 > \Delta U_3\)
- C \(Q_3 > Q_2 > Q_1\) and \(\Delta U_1=\Delta U_2=\Delta U_3\)
- D \(Q_3 > Q_2 > Q_1\) and \(\Delta U_1 > \Delta U_2 > \Delta U_3\)
Answer & Solution
Correct Answer
(A) \(Q_1 > Q_2 > Q_3\) and \(\Delta U_1=\Delta U_2=\Delta U_3\)
Step-by-step Solution
Detailed explanation
The internal energy of an ideal gas depends only on its temperature, which is a state function. Since all three processes start at state A and end at state B, the change in internal energy \(\Delta U\) is the same for all three paths. Therefore,…
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