COMEDK · Physics · 28. Atomic Physics
An electron of an atom transits from \(n_{1}\) to \(n_{2}\). In which of the following maximum frequency of photon will be emitted?
- A \(n_{1}=1\) to \(n_{2}=2\)
- B \(n_{1}=2\) to \(n_{2}=1\)
- C \(n_{1}=2\) to \(n_{2}=6\)
- D \(n_{1}=6\) to \(n_{2}=2\)
Answer & Solution
Correct Answer
(B) \(n_{1}=2\) to \(n_{2}=1\)
Step-by-step Solution
Detailed explanation
For emission of energy, electron of H-atom must fall from higher energy state to lower energy state. Hence, options (a) and (c) are not possible. In option (b), \(n_{1}=2, n_{2}=1\) \(\therefore\) Energy of emitted photon is given as…
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