COMEDK · Physics · 21. Magnetic Effects of Current
An electron moves with speed of \(2 \times 10^{5} \mathrm{~m} / \mathrm{s}\) along the positive \(x\)-direction in a magnetic field \(\mathbf{B}=(\hat{\mathbf{i}}-4 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}) \mathrm{T}\). The magnitude of the force (in N) experienced by the electron is
- A \(1.18 \times 10^{-13} \quad\)
- B \(1.28 \times 10^{-13}\)
- C \(1.6 \times 10^{-13} \quad\)
- D \(1.72 \times 10^{-13}\)
Answer & Solution
Correct Answer
(C) \(1.6 \times 10^{-13} \quad\)
Step-by-step Solution
Detailed explanation
Given, \(v=2 \times 10^{5} \mid \mathrm{im} / \mathrm{s}\) \(\mathbf{B}-(\hat{\mathbf{i}}-4 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}) \mathrm{T}\) Charge on electron, \(4=1.6 \times 10^{-14} \mathrm{C}\) \(\therefore\) Foree, \(\mathbf{F}=\hbar(v \times \mathbf{B})\)…
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