COMEDK · Physics · 17. Electrostatics
An electron is accelerated through a potential difference of \(45.5 \mathrm{~V}\). The velocity acquired by it (in \(\mathrm{ms}^{-1}\) ) is
- A \(4 \times 10^{6}\)
- B \(4 \times 10^{4}\)
- C \(10^{6}\)
- D zero
Answer & Solution
Correct Answer
(A) \(4 \times 10^{6}\)
Step-by-step Solution
Detailed explanation
Given, potential difference, \(V=45.5 \mathrm{~V}\) Velocity, \(v=\) ? Energy acquired by the electron after getling accelerated through the potential difference \(V\) is \(\mathrm{eV}\), which is equal to its kinetic energy. Hence, kinetic energy…
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