COMEDK · Physics · 21. Magnetic Effects of Current
An electric current \(I\) enters and leaves a uniform circular wire of radius \(r\) through diametrically opposite points. A charged particle \(q\) moves along the axis of circular wire passes through its centre with speed \(v\). The magnetic force on the particle when it passes through the centre has a magnitude
- A \(\dfrac{q v \mu_0 I}{2 \pi r}\)
- B \(q v \dfrac{\mu_0 I}{\pi r}\)
- C \(\dfrac{q \nu \mu_0 I}{r}\)
- D 0
Answer & Solution
Correct Answer
(D) 0
Step-by-step Solution
Detailed explanation
The circular wire is divided into two semi-circular segments by the diametrically opposite points where the current enters and leaves. Let the current \(I\) split into \(I_1\) and \(I_2\) through the two semi-circular paths. Since the wire is uniform, the resistance of each…
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