COMEDK · Physics · 19. Current Electricity
An electric coil is rated 400W, 200V. It is cut into two equal parts and connected in parallel to the same source of 200V. Calculate the percentage increase in energy produced per second.
- A \(300\ \%\)
- B \(400\ \%\)
- C \(200\ \%\)
- D \(100\ \%\)
Answer & Solution
Correct Answer
(A) \(300\ \%\)
Step-by-step Solution
Detailed explanation
Let the original resistance of the coil be \(R\). The original power is \(P_1 = \dfrac{V^2}{R} = 400\) W. When the coil is cut into two equal parts, the resistance of each part becomes \(\dfrac{R}{2}\). When these two parts are connected in parallel, the equivalent resistance…
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