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COMEDK · Physics · 22. Electromagnetic Induction

An aeroplane is flying horizontally with a velocity of \(360 \mathrm{~km} \mathrm{~h}^{-1}\). The distance between the tips of the wings of the aeroplane is \(50 \mathrm{~m}\). The vertical component of the earth's magnetic field is \(4 \times 10^{-4} \mathrm{Wbm}^{-2}\). The induced emf is

  1. A \(200 \mathrm{~V}\)
  2. B \(20 \mathrm{~V}\)
  3. C \(2 \mathrm{~V}\)
  4. D \(0.2 \mathrm{~V}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2 \mathrm{~V}\)

Step-by-step Solution

Detailed explanation

Given, velocity of aeroplane, \[ \begin{aligned} v &=360 \mathrm{kmh}^{-1} \\ &=360 \times \frac{5}{18} \mathrm{~ms}^{-1}=100 \mathrm{~ms}^{-1} \end{aligned} \] Distance between the tips of wings, \[ l=50 \mathrm{~m} \] Vertical component of earth's magnetic field,…