COMEDK · Physics · 22. Electromagnetic Induction
An aeroplane is flying horizontally with a velocity of \(360 \mathrm{~km} \mathrm{~h}^{-1}\). The distance between the tips of the wings of the aeroplane is \(50 \mathrm{~m}\). The vertical component of the earth's magnetic field is \(4 \times 10^{-4} \mathrm{Wbm}^{-2}\). The induced emf is
- A \(200 \mathrm{~V}\)
- B \(20 \mathrm{~V}\)
- C \(2 \mathrm{~V}\)
- D \(0.2 \mathrm{~V}\)
Answer & Solution
Correct Answer
(C) \(2 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given, velocity of aeroplane, \[ \begin{aligned} v &=360 \mathrm{kmh}^{-1} \\ &=360 \times \frac{5}{18} \mathrm{~ms}^{-1}=100 \mathrm{~ms}^{-1} \end{aligned} \] Distance between the tips of wings, \[ l=50 \mathrm{~m} \] Vertical component of earth's magnetic field,…
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