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COMEDK · Physics · 19. Current Electricity

A wire of uniform cross section and resistance 4 ohms is bent in the shape of square ABCD. Point A is connected to a point \(\mathrm{P}\) on DC by a wire AP of resistance \(1 \mathrm{ohm}\). When a potential difference is applied between \(\mathrm{A}\) and \(\mathrm{C}\), the points \(\mathrm{B}\) and \(\mathrm{P}\) are seen to be in same potential. What is the resistance of part \(\mathrm{DP}\) ?

  1. A 2 Ohm
  2. B \(\sqrt{2}-1
    \) Ohm
  3. C 1 Ohm
  4. D Zero Ohm
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{2}-1
\) Ohm

Step-by-step Solution

Detailed explanation

Each side of the square has resistance \(\dfrac{4}{4} = 1\ \Omega\). Let \(R_{DP} = x\), so \(R_{PC} = 1-x\). Since B and P are at the same potential, the A-P section resistance equals the P-C section resistance (by symmetry of the voltage divider). From A to P: direct wire AP…
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