COMEDK · Physics · 10. Mechanical Properties of Solids
A wire of length \(2 \mathrm{~m}\) is made from \(10 \mathrm{~cm}^{3}\) of copper. A force \(F\) is applied so that its length increases by \(2 \mathrm{~mm}\). Another wire of length \(8 \mathrm{~m}\) is made from the same volume of copper. If the force \(F\) is applied to it, its length will increase by
- A \(0.8 \mathrm{~cm}\)
- B \(1.6 \mathrm{~cm}\)
- C \(2.4 \mathrm{~cm}\)
- D \(3.2 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(D) \(3.2 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Given, change in length of wire, \(l_{1}=2 \mathrm{~mm}, l_{2}=\) ?, length of wire, \(L_{1}=2 \mathrm{~m}\) and length of another wire, \(L_{2}=8 \mathrm{~m}\) Change in length, \(l=\frac{F L}{A Y}=\frac{F L^{2}}{(A \cdot L) Y}=\frac{F L^{2}}{V Y}\) \([V=A \cdot L]\) where,…
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