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COMEDK · Physics · 19. Current Electricity

A wire of length 1m has a resistance of \(20\ \Omega\) at \(0^\circ\)C. It is uniformly stretched so that its length increases by 21%. Assuming the volume of the wire remains constant, the percentage change in resistance is \(n\%\). Alternatively, if the wire is heated [without stretching] through a temperature of \(27^\circ\) C and if the temperature coefficient of resistance of the material of wire is \(0.004K^{-1}\), the percentage change in resistance is \(m\%\). The values of \(m\) and \(n\) are:

  1. A 2.08 and 1.64
  2. B 1.08 and 4.64
  3. C 20.8 and 16.4
  4. D 10.8 and 46.4
Verified Solution

Answer & Solution

Correct Answer

(D) 10.8 and 46.4

Step-by-step Solution

Detailed explanation

For stretching of the wire, the volume \(V = A \cdot L\) remains constant. Resistance \(R = \rho \dfrac{L}{A} = \rho \dfrac{L^2}{V} \Rightarrow R \propto L^2\) Given that the length increases by \(21\%\), the new length is \(L' = 1.21 L\). New resistance…
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