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COMEDK · Physics · 8. Rotational Motion

A wheel is free to rotate about a horizontal axis through O. A force of \(200 \mathrm{~N}\) is applied at a point \(\mathrm{P} 2 \mathrm{~cm}\) from the center \(\mathrm{O}\). OP makes an angle of \(55^{\circ}\) with \(\mathrm{x}\) axis and the force is in the plane of the wheel making an angle of \(25^{\circ}\) with the horizontal axis. What is the torque?

  1. A 3.2 N m
  2. B 2 N m
  3. C 4 N m
  4. D 3.4 N m
Verified Solution

Answer & Solution

Correct Answer

(B) 2 N m

Step-by-step Solution

Detailed explanation

The torque \(\vec{\tau}\) is defined as \(\vec{\tau} = \vec{r} \times \vec{F}\), where \(\vec{r}\) is the position vector of the point of application P relative to the axis O, and \(\vec{F}\) is the applied force. The magnitude of the torque is given by…