COMEDK · Physics · 17. Electrostatics
A uniformly charged conducting sphere of 0.2 m diameter has a surface charge density of \(70 \mu \mathrm{Cm}^{-2}\). The electric flux leaving the surface of the sphere is:
- A \(9.9 \times 10^6 N C^{-1} m^2\)
- B \(8.9 \times 10^6 N C^{-1} m^2\)
- C \(8.9 \times 10^5 N C^{-1} m^2\)
- D \(9.9 \times 10^5 N C^{-1} m^2\)
Answer & Solution
Correct Answer
(D) \(9.9 \times 10^5 N C^{-1} m^2\)
Step-by-step Solution
Detailed explanation
The diameter of the sphere is \(d = 0.2\) m, so the radius is \(r = 0.1\) m. The surface area of the sphere is \(A = 4 \pi r^2 = 4 \pi (0.1)^2 = 0.04 \pi\) m\(^2\). The total charge \(Q\) on the sphere is given by \(Q = \sigma A\), where \(\sigma = 70 \times 10^{-6}\) C…
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