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COMEDK · Physics · 8. Rotational Motion

A thin circular ring of mass \(M\) and radius \(R\) rotates about an axis through its centre and perpendicular to its plane, with a constant angular velocity \(\omega\). Four small spheres each of mass \(m\) (negligible radius) are kept gently to the opposite ends of two mutually perpendicular diameters of the ring. The new angular velocity of the ring will be

  1. A \(\left(\frac{M+4 m}{M}\right) \omega\)
  2. B \(\frac{M}{4 m} \omega\)
  3. C \(\left(\frac{M}{M+4 m}\right) \omega\)
  4. D \(\left(\frac{M}{M-4 m}\right) \omega\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left(\frac{M}{M+4 m}\right) \omega\)

Step-by-step Solution

Detailed explanation

According to conservation of angular momentum, \(I \omega=\text { constant }\) i.e. we can write,…