COMEDK · Physics · 16. Waves and Sound
A string vibrates with a frequency of \(200 \mathrm{~Hz}\). When its length is doubled and tension is altered, it begins to vibrate with a frequency of \(300 \mathrm{~Hz}\). The ratio of the new tension to the original tension is
- A 9:1
- B \(1: 9\)
- C \(3: 1\)
- D \(1: 3\)
Answer & Solution
Correct Answer
(A) 9:1
Step-by-step Solution
Detailed explanation
Given, \(L_{2}=2 L_{1}, f_{1}=200 \mathrm{~Hz}, f_{2}=300 \mathrm{~Hz}\) We know that, frequency of vibrating string is given as \[ f=\frac{1}{2 L} \sqrt{\frac{T}{\mu}} \] where, \(\mu=\) mass per unit length of string and \(L=\) length of the string.…
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