COMEDK · Physics · 21. Magnetic Effects of Current
A straight wire of length \(2 \mathrm{~m}\) carries a current of \(10 \mathrm{~A}\). If this wire is placed in uniform magnetic field of \(0.15 \mathrm{~T}\) making an angle of \(45^{\circ}\) with the magnetic field, the applied force on the wire will be
- A \(1.5 \mathrm{~N}\)
- B \(3 \mathrm{~N}\)
- C \(3 \sqrt{2} \mathrm{~N}\)
- D \(3 / \sqrt{2} \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(3 / \sqrt{2} \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Given, \(\begin{aligned} & i=10 \mathrm{~A}, B=0.15 \mathrm{~T}, \\ & \theta=45^{\circ} \text { and } l=2 \mathrm{~m} \end{aligned}\) Here, \(F=i l B \sin \theta=10 \times 2 \times 0.15 \sin 45^{\circ}=\frac{3}{\sqrt{2}} \mathrm{~N}\)
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