COMEDK · Physics · 5. Laws of Motion
A stone of mass \(2 \mathrm{~kg}\) is hung from the ceiling of the room using two strings. If the strings make an angle \(60^{\circ}\) and \(30^{\circ}\) respectively with the horizontal surface of the roof then the tension on the longer string is : \(g=10 \mathrm{~ms}^{-2}\)
- A \(10 \sqrt{3} \mathrm{~N}\)
- B \(\sqrt{3} \mathrm{~N}\)
- C \(10 \mathrm{~N}\)
- D \(\dfrac{\sqrt{3}}{2} \mathrm{~N}\)
Answer & Solution
Correct Answer
(C) \(10 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
The string making \(30°\) with the horizontal is longer. Let \(T_1\) and \(T_2\) be tensions in strings at \(60°\) and \(30°\) respectively. Weight \(W = mg = 20\) N. Horizontal equilibrium: \(T_1\cos60° = T_2\cos30°\)…
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