COMEDK · Physics · 3. Motion In One Dimension
A stone dropped from the top of the tower reaches ground in \(4 \mathrm{~s}\). Height of the tower is \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
- A \(20 \mathrm{~m}\)
- B \(40 \mathrm{~m}\)
- C \(60 \mathrm{~m}\)
- D \(80 \mathrm{~m}\)
Answer & Solution
Correct Answer
(D) \(80 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, \(t=4 \mathrm{~s}, u=0, g=10 \mathrm{~ms}^{-2}\) Using equation of motion, \(h=u t+\frac{1}{2} g t^{2}=\frac{1}{2} g t^{2}=\frac{1}{2} \times 10 \times(4)^{2}=80 \mathrm{~m}\)
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