COMEDK · Physics · 21. Magnetic Effects of Current
A square wire of each side l carries a current \(I\). The magnetic field at the mid-point of the square
- A \(8 \sqrt{2} \dfrac{\mu_0}{4 \pi} \dfrac{I}{l}\)
- B \(32 \sqrt{2} \dfrac{\mu_0}{4 \pi} \dfrac{I}{l}\)
- C \(4 \sqrt{2} \dfrac{\mu_0}{4 \pi} \dfrac{I}{l}\)
- D \(16 \sqrt{2} \dfrac{\mu_0}{4 \pi} \dfrac{I}{l}\)
Answer & Solution
Correct Answer
(A) \(8 \sqrt{2} \dfrac{\mu_0}{4 \pi} \dfrac{I}{l}\)
Step-by-step Solution
Detailed explanation
Magnetic field due to a finite wire at perpendicular distance \(d\) is \(B = \dfrac{\mu_0 I}{4\pi d}(\sin\theta_1 + \sin\theta_2)\), where \(\theta_1\) and \(\theta_2\) are angles subtended by the ends of the wire at the point. For the center of the square, perpendicular…
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