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COMEDK · Physics · 26. Wave Optics

A source of light of wavelength \(5000 Å\) is placed at one end of a table \(2 \mathrm{~m}\) long and \(5 \mathrm{~mm}\) above its flat well polished top. The fringe width of the interference bands seen on a screen located at the end of the table is

  1. A \(2 \times 10^{-5} \mathrm{~m}\)
  2. B \(2 \times 10^{-4} \mathrm{~m}\)
  3. C \(2 \times 10^{-3} \mathrm{~m}\)
  4. D \(2 \times 10^{-2} \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \times 10^{-4} \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

Given, wavelength of light used, \[ \begin{aligned} \lambda &=5000 Å=5 \times 10^{-7} \mathrm{~m} \\ D &=2 \mathrm{~m} \\ d &=5 \mathrm{~mm}=5 \times 10^{-3} \mathrm{~m} \end{aligned} \] \(\therefore\) Fringe width, \(\beta=\frac{D \lambda}{d}\)…