COMEDK · Physics · 23. Alternating Current
A sinusoidal voltage of peak value \(300 \mathrm{~V}\) and an angular frequency \(\omega=400 \mathrm{rads}^{-1}\) is applied to series \(L-C-R\) circuit, in which \(R=3 \Omega\), \(L=20 \mathrm{mH}\) and \(C=625 \mu \mathrm{F}\). The peak current in the circuit is
- A \(30 \sqrt{2} \mathrm{~A}\)
- B \(60 \mathrm{~A}\)
- C \(100 \mathrm{~A} \quad\)
- D \(60 \sqrt{2} \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(60 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Given, \(V_{m}=300 \mathrm{~V}, \omega=400 \mathrm{rads}^{-1}\) \[ R=3 \Omega, L=20 \mathrm{mH}=20 \times 10^{-3} \mathrm{H} \] and \(C=625 \mu \mathrm{F}=625 \times 10^{-6} \mathrm{~F}\) Impedance of the circuit, \[ Z=\sqrt{R^{2}+\left(X_{L}-X_{C}\right)^{2}} \] Here,…
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