COMEDK · Physics · 21. Magnetic Effects of Current
A short bar magnet placed with its axis at \(45^{\circ}\) with an external field of \(400 \times 10^{-4} \mathrm{~T}\) experiences a torque of 0.024 Nm . If a solenoid of cross-sectional area \(10^{-4} \mathrm{~m}^2\) and 500 turns replaces the short bar magnet such that they have the same magnetic moment, then the current flowing through the solenoid is:
- A \(4 \sqrt{2} \mathrm{~A}\)
- B \(5 \sqrt{2} \mathrm{~A}\)
- C \(2 \sqrt{2} \mathrm{~A}\)
- D \(12 \sqrt{2} \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(12 \sqrt{2} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
The torque \(\tau\) experienced by a magnetic dipole in an external magnetic field \(B\) is given by \(\tau = mB \sin \theta\), where \(m\) is the magnetic moment and \(\theta\) is the angle between the magnetic moment and the magnetic field. Given \(\tau = 0.024 \text{ Nm}\),…
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