COMEDK · Physics · 23. Alternating Current
A series LCR circuit is connected to an AC source of 120 V and 60 Hz . The value of resistance R in the circuit is \(100 \Omega\).A voltmeter reads the voltage across R as 50 V , across the inductor as 132 V and across the capacitor as \(\dfrac{70}{6.6} \mathrm{~V}\). The value of inductance and capacitance in the circuit is:
- A 0.7 H and \(125 \mu \mathrm{~F}\)
- B 7 H and \(0.0125 \mu \mathrm{~F}\)
- C 0.07 H and \(0.0125 \mu \mathrm{~F}\)
- D 0.007 and \(12.5 \mu \mathrm{~F}\)
Answer & Solution
Correct Answer
(A) 0.7 H and \(125 \mu \mathrm{~F}\)
Step-by-step Solution
Detailed explanation
Given \(V_{R} = 50 \text{ V}\), \(V_{L} = 132 \text{ V}\), \(V_{C} = \dfrac{70}{6.6} \text{ V} \approx 10.6 \text{ V}\), and \(R = 100 \Omega\). The current in the series LCR circuit is \(I = \dfrac{V_{R}}{R} = \dfrac{50}{100} = 0.5 \text{ A}\). The inductive reactance \(X_{L}\)…
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