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COMEDK · Physics · 26. Wave Optics

A screen is placed \(2 \mathrm{~m}\) away from a narrow slit. It the first minimum lies 5 mm from either side of the central maxima, when plane waves of wavelength \(5 \times 10^{-7} \mathrm{~m}\) are used, the slit width is

  1. A \(4.8 \times 10^{-4} \mathrm{~m}\)
  2. B \(2 \times 10^{-4} \mathrm{~m}\)
  3. C \(5 \times 10^{-4} \mathrm{~m}\)
  4. D \(24 \times 10^{-4} \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \times 10^{-4} \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

Given, distance between source and screen, \(D=2 \mathrm{~m}\) Distance of first minimum from the central maximum, \(y=5 \mathrm{~mm}=5 \times 10^{-3} \mathrm{~m}\) Wavelength, \(\lambda=5 \times 10^{-7} \mathrm{~m}\) We know that, \[ y_{n}=\frac{n \lambda D}{d} \] For first…