COMEDK · Physics · 26. Wave Optics
A screen is placed \(2 \mathrm{~m}\) away from a narrow slit. It the first minimum lies 5 mm from either side of the central maxima, when plane waves of wavelength \(5 \times 10^{-7} \mathrm{~m}\) are used, the slit width is
- A \(4.8 \times 10^{-4} \mathrm{~m}\)
- B \(2 \times 10^{-4} \mathrm{~m}\)
- C \(5 \times 10^{-4} \mathrm{~m}\)
- D \(24 \times 10^{-4} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{-4} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, distance between source and screen, \(D=2 \mathrm{~m}\) Distance of first minimum from the central maximum, \(y=5 \mathrm{~mm}=5 \times 10^{-3} \mathrm{~m}\) Wavelength, \(\lambda=5 \times 10^{-7} \mathrm{~m}\) We know that, \[ y_{n}=\frac{n \lambda D}{d} \] For first…
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