COMEDK · Physics · 6. Work Power Energy
A scooter moves with a speed of \(7 \mathrm{~ms}^{-1}\), on a straight road and is stopped by applying the brakes. Before stopping, the scooter travels \(10 \mathrm{~m}\). If the weight of the scooter is \(\mathrm{W}\), then the total resistance to the motion of the scooter will be
- A 2W
- B \(\dfrac{1}{2} W\)
- C \(\dfrac{1}{4} W\)
- D 4W
Answer & Solution
Correct Answer
(C) \(\dfrac{1}{4} W\)
Step-by-step Solution
Detailed explanation
Given initial speed \(u = 7 \mathrm{~ms}^{-1}\), final speed \(v = 0\), and distance \(s = 10 \mathrm{~m}\). Using the equation of motion \(v^2 = u^2 + 2as\), we have \(0 = 7^2 + 2a(10)\). \(0 = 49 + 20a \Rightarrow a = -\dfrac{49}{20} \mathrm{~ms}^{-2}\). The retarding force…
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