COMEDK · Physics · 8. Rotational Motion
A ring rolls down an inclined plane. The ratio of the rotational kinetic energy to translational kinetic energy is
- A \(1: 3\)
- B \(1: 1\)
- C \(3: 1\)
- D \(2: 1\)
Answer & Solution
Correct Answer
(B) \(1: 1\)
Step-by-step Solution
Detailed explanation
The rotational kinetic energy of a ring is \[ K_{R}=\frac{1}{2} I \omega^{2} \] For a ring, \(\quad {I}=M R^{2}\) and \(\omega=\frac{v}{R}\) \[ \therefore \quad K_{R}=\frac{1}{2}\left(M R^{2}\right) \times\left(\frac{v}{R}\right)^{2}=\frac{1}{2} M v^{2} \] Also, translational…
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