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COMEDK · Physics · 25. Ray Optics

A ray of light falls upon a \(60^{\circ}\) prism \((\mu=\sqrt{2})\) and it suffers minimum deviation. The angle of incidence for this ray must be

  1. A \(30^{\circ}\)
  2. B \(45^{\circ}\)
  3. C \(60^{\circ}\)
  4. D \(75^{\circ}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(45^{\circ}\)

Step-by-step Solution

Detailed explanation

Given, angle of prism, \(A=60^{\circ}\) \[ \mu=\sqrt{2} \] We know that, \(\mu=\frac{\sin \left(\frac{A+\delta_{m}}{2}\right)}{\sin A / 2}\) \(\Rightarrow \quad \sqrt{2}=\frac{\sin \left(\frac{60^{\circ}+\delta_{m}}{2}\right)}{\sin \frac{60}{2}}\)…