COMEDK · Physics · 25. Ray Optics
A ray of light falls upon a \(60^{\circ}\) prism \((\mu=\sqrt{2})\) and it suffers minimum deviation. The angle of incidence for this ray must be
- A \(30^{\circ}\)
- B \(45^{\circ}\)
- C \(60^{\circ}\)
- D \(75^{\circ}\)
Answer & Solution
Correct Answer
(B) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
Given, angle of prism, \(A=60^{\circ}\) \[ \mu=\sqrt{2} \] We know that, \(\mu=\frac{\sin \left(\frac{A+\delta_{m}}{2}\right)}{\sin A / 2}\) \(\Rightarrow \quad \sqrt{2}=\frac{\sin \left(\frac{60^{\circ}+\delta_{m}}{2}\right)}{\sin \frac{60}{2}}\)…
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