COMEDK · Physics · 27. Dual Nature of Matter
A proton and an alpha particle are subjected to same potential difference \(V\). Their de-Broglie wavelengths \(\lambda_{p}, \lambda_{\alpha}\) will be in the ratio
- A \(2: 1\)
- B \(2 \sqrt{2}: 1\)
- C \(1: 1\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(B) \(2 \sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
T he de-Broglie wavelength of a particle is given by \(\lambda=\frac{h}{m v}=\frac{h}{p}\) The momentum of proton, \(p_{p}=\sqrt{2 m E}=\sqrt{2 m e V}\) Similarly, for \(\alpha\) - particle,…
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