COMEDK · Physics · 8. Rotational Motion
A point marked on a ring of radius 2 cm is in contact with a horizontal plane. Now the ring is rolled forward half a revolution along the positive X - direction. Then the angle made by the displacement vector of the point with the X - axis is:
- A \(\theta=\cot ^{-1}\left(\dfrac{2}{\pi}\right)\)
- B \(\theta=\tan ^{-1}\left(\dfrac{2}{3 \pi}\right)\)
- C \(\theta=\tan ^{-1}\left(\dfrac{2 \pi}{3}\right)\)
- D \(\theta=\tan ^{-1}\left(\dfrac{2}{\pi}\right)\)
Answer & Solution
Correct Answer
(D) \(\theta=\tan ^{-1}\left(\dfrac{2}{\pi}\right)\)
Step-by-step Solution
Detailed explanation
Let the radius of the ring be \(R = 2\) cm. Initially, the point is at the origin \((0, 0)\) in contact with the horizontal plane (X-axis). The ring rolls forward by half a revolution. The distance moved by the center of the ring is…
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