COMEDK · Physics · 9. Gravitation
A planet has double the mass of the earth and double the radius. The gravitational potential at the surface of the Earth is \(\mathrm{V}\) and the magnitude of the gravitational field strength is \(\mathrm{g}\). The gravitational potential and gravitational field strength on the surface of the planet are
| No. | Potential | Field |
|---|---|---|
| A | V | \(\dfrac{g}{4}\) |
| B | 2V | \(\dfrac{g}{2}\) |
| C | V | \(\dfrac{g}{2}\) |
| D | 2V | \(\dfrac{g}{4}\) |
- A A
- B B
- C D
- D C
Answer & Solution
Correct Answer
(D) C
Step-by-step Solution
Detailed explanation
The gravitational potential \(V\) at the surface of a planet of mass \(M\) and radius \(R\) is given by \(V = -\dfrac{GM}{R}\). The gravitational field strength \(g\) at the surface is given by \(g = \dfrac{GM}{R^2}\). For the Earth, \(V_E = -\dfrac{GM_E}{R_E} = V\) and…
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