COMEDK · Physics · 15. Oscillations
A partiele exeeutes a linear SHM with an amplitude of \(4 \mathrm{~cm}\). At the mean position the velocity of the particle is \(10 \mathrm{~cm} / \mathrm{s}\). What is the displacement of the particle when its speed becomes \(5 \mathrm{~cm} / \mathrm{s}\) ?
- A \(2(\sqrt{3}) \mathrm{cm}\)
- B \(2(\sqrt{5}) \mathrm{cm}\)
- C \(\sqrt{5} \mathrm{~cm}\)
- D \(\sqrt{3} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(2(\sqrt{3}) \mathrm{cm}\)
Step-by-step Solution
Detailed explanation
Amplitude of the particle is SHM, \[ \mathrm{A}=4 \mathrm{~cm} \] At mean position velocity, \[ \begin{aligned} & v_{\max } &=10 \mathrm{~cm} / \mathrm{s} \\ \Rightarrow \quad A \omega &=10 \end{aligned} \] \begin{aligned} \Rightarrow \quad \omega &=\frac{10}{A} \\…
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