COMEDK · Physics · 17. Electrostatics
A particle ' \(X\) ' carrying a charge \(+Q\) is moving in a circular path of radius \(R\) around another particle ' \(Y\) ' having a charge \(-Q\) with a frequency ' \(v\) '. Then the mass ' \(m\) ' of the charged particle is
- A \(M=\dfrac{Q^2}{\left[16 \pi^3 \varepsilon_0 R^2 v^2\right]}\)
- B \(M=\dfrac{Q^2}{\left[16 \pi^2 \varepsilon_0 R v^2\right]}\)
- C \(M=\dfrac{Q^2}{\left[16 \pi^2 \varepsilon_0 R^3 v^2\right]}\)
- D \(M=\dfrac{Q^2}{\left[16 \pi^3 \varepsilon_0 R^3 v^2\right]}\)
Answer & Solution
Correct Answer
(D) \(M=\dfrac{Q^2}{\left[16 \pi^3 \varepsilon_0 R^3 v^2\right]}\)
Step-by-step Solution
Detailed explanation
The electrostatic force between the two charges \(Q\) and \(-Q\) separated by a distance \(R\) provides the necessary centripetal force for the circular motion of particle \(X\). The electrostatic force is given by Coulomb's law as…
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